Properties

Label 324000.bm.288.c1
Order $ 3^{2} \cdot 5^{3} $
Index $ 2^{5} \cdot 3^{2} $
Normal No

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Subgroup ($H$) information

Description:$C_5\times C_{15}^2$
Order: \(1125\)\(\medspace = 3^{2} \cdot 5^{3} \)
Index: \(288\)\(\medspace = 2^{5} \cdot 3^{2} \)
Exponent: \(15\)\(\medspace = 3 \cdot 5 \)
Generators: $d^{20}f^{10}, d^{6}e^{12}, e^{3}f^{9}, e^{10}f^{5}, f^{3}$ Copy content Toggle raw display
Nilpotency class: $1$
Derived length: $1$

The subgroup is abelian (hence nilpotent, solvable, supersolvable, monomial, metabelian, and an A-group).

Ambient group ($G$) information

Description: $C_{15}^3.(C_4\times S_4)$
Order: \(324000\)\(\medspace = 2^{5} \cdot 3^{4} \cdot 5^{3} \)
Exponent: \(180\)\(\medspace = 2^{2} \cdot 3^{2} \cdot 5 \)
Derived length:$4$

The ambient group is nonabelian and solvable. Whether it is monomial has not been computed.

Automorphism information

While the subgroup $H$ is not characteristic, the stabilizer $S$ of $H$ in the automorphism group $\operatorname{Aut}(G)$ of the ambient group acts on $H$, yielding a homomorphism $\operatorname{res} : S \to \operatorname{Aut}(H)$. The image of $\operatorname{res}$ on the inner automorphisms $\operatorname{Inn}(G) \cap S$ is the Weyl group $W = N_G(H) / Z_G(H)$.

$\operatorname{Aut}(G)$$D_{15}\wr S_3.C_4$, of order \(648000\)\(\medspace = 2^{6} \cdot 3^{4} \cdot 5^{3} \)
$\operatorname{Aut}(H)$ $\GL(2,3)\times C_4.\PSL(3,5)$
$W$$C_4\times S_3$, of order \(24\)\(\medspace = 2^{3} \cdot 3 \)

Related subgroups

Centralizer:$C_{15}^3$
Normalizer:$C_{15}\wr S_3:C_4$
Normal closure:$C_{15}^3$
Core:$C_5^3$
Minimal over-subgroups:$C_{15}^3$$C_{15}^2:C_{15}$$C_{15}^2.C_{15}$$C_5^3:(C_3\times S_3)$$C_3^2\times C_5^2:D_5$$C_5^3:(C_3\times S_3)$
Maximal under-subgroups:$C_5^2\times C_{15}$$C_5^2\times C_{15}$$C_{15}^2$$C_{15}^2$$C_{15}^2$$C_{15}^2$$C_{15}^2$$C_{15}^2$$C_{15}^2$$C_{15}^2$$C_{15}^2$

Other information

Number of subgroups in this autjugacy class$4$
Number of conjugacy classes in this autjugacy class$1$
Möbius function not computed
Projective image$C_{15}^3.(C_4\times S_4)$