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Group invariants
Abstract group: | $C_5\times \He_3$ |
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Order: | $135=3^{3} \cdot 5$ |
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Cyclic: | no |
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Abelian: | no |
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Solvable: | yes |
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Nilpotency class: | $2$ |
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Group action invariants
Degree $n$: | $45$ |
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Transitive number $t$: | $11$ |
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Parity: | $1$ |
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Primitive: | no |
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$\card{\Aut(F/K)}$: | $15$ |
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Generators: | $(1,34,23,10,45,33,21,9,41,30,17,5,39,25,14)(2,36,22,12,44,32,20,7,40,29,18,4,37,27,13)(3,35,24,11,43,31,19,8,42,28,16,6,38,26,15)$, $(1,45,40,39,34,32,30,25,22,21,17,13,10,9,4)(2,44,42,37,36,31,29,27,24,20,18,15,12,7,6)(3,43,41,38,35,33,28,26,23,19,16,14,11,8,5)$ |
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Low degree resolvents
$\card{(G/N)}$ Galois groups for stem field(s) $3$: $C_3$ x 4 $5$: $C_5$ $9$: $C_3^2$ $15$: $C_{15}$ x 4 $27$: $C_3^2:C_3$ $45$: 45T2 Resolvents shown for degrees $\leq 47$
Subfields
Degree 3: $C_3$
Degree 5: $C_5$
Degree 9: $C_3^2:C_3$
Degree 15: $C_{15}$
Low degree siblings
45T11 x 3Siblings are shown with degree $\leq 47$
A number field with this Galois group has no arithmetically equivalent fields.
Conjugacy classes
Conjugacy classes not computed
Character table
55 x 55 character table
Regular extensions
Data not computed