Properties

Label 768.1090235.12.l1
Order $ 2^{6} $
Index $ 2^{2} \cdot 3 $
Normal No

Downloads

Learn more

Subgroup ($H$) information

Description:$C_2^6$
Order: \(64\)\(\medspace = 2^{6} \)
Index: \(12\)\(\medspace = 2^{2} \cdot 3 \)
Exponent: \(2\)
Generators: $\langle(1,4)(2,7)(3,5)(6,8)(11,12)(13,14), (1,5)(2,7)(3,4)(6,8)(9,10)(13,14), (2,7) \!\cdots\! \rangle$ Copy content Toggle raw display
Nilpotency class: $1$
Derived length: $1$

The subgroup is abelian (hence nilpotent, solvable, supersolvable, monomial, metabelian, and an A-group), a $p$-group (hence elementary and hyperelementary), and rational.

Ambient group ($G$) information

Description: $C_2^5:S_4$
Order: \(768\)\(\medspace = 2^{8} \cdot 3 \)
Exponent: \(12\)\(\medspace = 2^{2} \cdot 3 \)
Derived length:$3$

The ambient group is nonabelian, monomial (hence solvable), and rational.

Automorphism information

While the subgroup $H$ is not characteristic, the stabilizer $S$ of $H$ in the automorphism group $\operatorname{Aut}(G)$ of the ambient group acts on $H$, yielding a homomorphism $\operatorname{res} : S \to \operatorname{Aut}(H)$. The image of $\operatorname{res}$ on the inner automorphisms $\operatorname{Inn}(G) \cap S$ is the Weyl group $W = N_G(H) / Z_G(H)$.

$\operatorname{Aut}(G)$$C_2^7.(S_3\times \GL(3,2))$, of order \(129024\)\(\medspace = 2^{11} \cdot 3^{2} \cdot 7 \)
$\operatorname{Aut}(H)$ $\GL(6,2)$, of order \(20158709760\)\(\medspace = 2^{15} \cdot 3^{4} \cdot 5 \cdot 7^{2} \cdot 31 \)
$\operatorname{res}(S)$$S_4$, of order \(24\)\(\medspace = 2^{3} \cdot 3 \)
$\card{\operatorname{ker}(\operatorname{res})}$\(128\)\(\medspace = 2^{7} \)
$W$$C_1$, of order $1$

Related subgroups

Centralizer:$C_2^7$
Normalizer:$C_2^7$
Normal closure:$C_2^7$
Core:$C_2^2$
Minimal over-subgroups:$C_2^7$
Maximal under-subgroups:$C_2^5$$C_2^5$$C_2^5$$C_2^5$$C_2^5$$C_2^5$$C_2^5$$C_2^5$

Other information

Number of subgroups in this autjugacy class$42$
Number of conjugacy classes in this autjugacy class$7$
Möbius function$0$
Projective image$C_2^5:S_4$