Subgroup ($H$) information
Description: | not computed |
Order: | \(13500\)\(\medspace = 2^{2} \cdot 3^{3} \cdot 5^{3} \) |
Index: | \(24\)\(\medspace = 2^{3} \cdot 3 \) |
Exponent: | not computed |
Generators: |
$b^{3}, f^{10}, e^{3}f^{9}, d^{20}e^{10}, d^{6}e^{12}, f^{3}, b^{6}, e^{10}f^{5}$
|
Derived length: | not computed |
The subgroup is characteristic (hence normal), a semidirect factor, nonabelian, supersolvable (hence solvable and monomial), metabelian, and an A-group. Whether it is elementary, hyperelementary, monomial, simple, quasisimple, perfect, almost simple, or rational has not been computed.
Ambient group ($G$) information
Description: | $C_{15}^3.(C_4\times S_4)$ |
Order: | \(324000\)\(\medspace = 2^{5} \cdot 3^{4} \cdot 5^{3} \) |
Exponent: | \(180\)\(\medspace = 2^{2} \cdot 3^{2} \cdot 5 \) |
Derived length: | $4$ |
The ambient group is nonabelian and solvable. Whether it is monomial has not been computed.
Quotient group ($Q$) structure
Description: | $S_4$ |
Order: | \(24\)\(\medspace = 2^{3} \cdot 3 \) |
Exponent: | \(12\)\(\medspace = 2^{2} \cdot 3 \) |
Automorphism Group: | $S_4$, of order \(24\)\(\medspace = 2^{3} \cdot 3 \) |
Outer Automorphisms: | $C_1$, of order $1$ |
Derived length: | $3$ |
The quotient is nonabelian, monomial (hence solvable), and rational.
Automorphism information
Since the subgroup $H$ is characteristic, the automorphism group $\operatorname{Aut}(G)$ of the ambient group acts on $H$, yielding a homomorphism $\operatorname{res} : \operatorname{Aut}(G) \to \operatorname{Aut}(H)$. The image of $\operatorname{res}$ on the inner automorphism group $\operatorname{Inn}(G)$ is the Weyl group $W = G / Z_G(H)$.
$\operatorname{Aut}(G)$ | $D_{15}\wr S_3.C_4$, of order \(648000\)\(\medspace = 2^{6} \cdot 3^{4} \cdot 5^{3} \) |
$\operatorname{Aut}(H)$ | not computed |
$W$ | $C_{15}^3.(C_4\times S_4)$, of order \(324000\)\(\medspace = 2^{5} \cdot 3^{4} \cdot 5^{3} \) |
Related subgroups
Other information
Number of conjugacy classes in this autjugacy class | $1$ |
Möbius function | not computed |
Projective image | $C_{15}^3.(C_4\times S_4)$ |