Properties

Label 324000.bm.1620.b1
Order $ 2^{3} \cdot 5^{2} $
Index $ 2^{2} \cdot 3^{4} \cdot 5 $
Normal No

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Subgroup ($H$) information

Description:$C_{10}:F_5$
Order: \(200\)\(\medspace = 2^{3} \cdot 5^{2} \)
Index: \(1620\)\(\medspace = 2^{2} \cdot 3^{4} \cdot 5 \)
Exponent: \(20\)\(\medspace = 2^{2} \cdot 5 \)
Generators: $acd^{15}e^{4}f^{8}, b^{6}, d^{6}e^{12}f^{6}, b^{3}, e^{3}f^{9}$ Copy content Toggle raw display
Derived length: $2$

The subgroup is nonabelian, supersolvable (hence solvable and monomial), metabelian, and an A-group.

Ambient group ($G$) information

Description: $C_{15}^3.(C_4\times S_4)$
Order: \(324000\)\(\medspace = 2^{5} \cdot 3^{4} \cdot 5^{3} \)
Exponent: \(180\)\(\medspace = 2^{2} \cdot 3^{2} \cdot 5 \)
Derived length:$4$

The ambient group is nonabelian and solvable. Whether it is monomial has not been computed.

Automorphism information

While the subgroup $H$ is not characteristic, the stabilizer $S$ of $H$ in the automorphism group $\operatorname{Aut}(G)$ of the ambient group acts on $H$, yielding a homomorphism $\operatorname{res} : S \to \operatorname{Aut}(H)$. The image of $\operatorname{res}$ on the inner automorphisms $\operatorname{Inn}(G) \cap S$ is the Weyl group $W = N_G(H) / Z_G(H)$.

$\operatorname{Aut}(G)$$D_{15}\wr S_3.C_4$, of order \(648000\)\(\medspace = 2^{6} \cdot 3^{4} \cdot 5^{3} \)
$\operatorname{Aut}(H)$ $(C_5\times C_{10}):\GL(2,5)$, of order \(24000\)\(\medspace = 2^{6} \cdot 3 \cdot 5^{3} \)
$W$$D_5:F_5$, of order \(200\)\(\medspace = 2^{3} \cdot 5^{2} \)

Related subgroups

Centralizer:$C_2$
Normalizer:$D_{10}:F_5$
Normal closure:$C_{15}^3.(C_4\times S_4)$
Core:$C_1$
Minimal over-subgroups:$C_5^3:(C_2\times C_4)$$C_{30}:F_5$$C_{30}:F_5$$C_{30}:F_5$$S_3\times C_5:F_5$$D_{10}:F_5$
Maximal under-subgroups:$C_5:D_{10}$$C_5:F_5$$C_5:F_5$$C_2\times F_5$$C_2\times F_5$$C_2\times F_5$$C_2\times F_5$

Other information

Number of subgroups in this autjugacy class$810$
Number of conjugacy classes in this autjugacy class$1$
Möbius function not computed
Projective image$C_{15}^3.(C_4\times S_4)$