Properties

Label 108000.b.1200.q1
Order $ 2 \cdot 3^{2} \cdot 5 $
Index $ 2^{4} \cdot 3 \cdot 5^{2} $
Normal No

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Subgroup ($H$) information

Description:$C_3^2\times D_5$
Order: \(90\)\(\medspace = 2 \cdot 3^{2} \cdot 5 \)
Index: \(1200\)\(\medspace = 2^{4} \cdot 3 \cdot 5^{2} \)
Exponent: \(30\)\(\medspace = 2 \cdot 3 \cdot 5 \)
Generators: $a^{2}c^{4}d^{13}e^{4}f^{3}, c^{2}d^{20}, d^{18}e^{3}, d^{20}$ Copy content Toggle raw display
Derived length: $2$

The subgroup is nonabelian, metacyclic (hence solvable, supersolvable, monomial, and metabelian), and an A-group.

Ambient group ($G$) information

Description: $D_5^3.C_3^2:D_6$
Order: \(108000\)\(\medspace = 2^{5} \cdot 3^{3} \cdot 5^{3} \)
Exponent: \(60\)\(\medspace = 2^{2} \cdot 3 \cdot 5 \)
Derived length:$4$

The ambient group is nonabelian and solvable. Whether it is monomial has not been computed.

Automorphism information

While the subgroup $H$ is not characteristic, the stabilizer $S$ of $H$ in the automorphism group $\operatorname{Aut}(G)$ of the ambient group acts on $H$, yielding a homomorphism $\operatorname{res} : S \to \operatorname{Aut}(H)$. The image of $\operatorname{res}$ on the inner automorphisms $\operatorname{Inn}(G) \cap S$ is the Weyl group $W = N_G(H) / Z_G(H)$.

$\operatorname{Aut}(G)$$D_5^3:\He_3.C_2^3$, of order \(216000\)\(\medspace = 2^{6} \cdot 3^{3} \cdot 5^{3} \)
$\operatorname{Aut}(H)$ $F_5\times \GL(2,3)$, of order \(960\)\(\medspace = 2^{6} \cdot 3 \cdot 5 \)
$W$$C_{30}:C_4$, of order \(120\)\(\medspace = 2^{3} \cdot 3 \cdot 5 \)

Related subgroups

Centralizer:$C_3^2$
Normalizer:$C_3^2:(S_3\times F_5)$
Normal closure:$C_3^2\times C_5^2:D_5$
Core:$C_3^2$
Minimal over-subgroups:$C_{15}^2:C_2$$C_{15}^2:C_2$$D_5\times \He_3$$C_{15}:D_6$$C_{15}:C_{12}$$C_{15}:C_{12}$
Maximal under-subgroups:$C_3\times C_{15}$$C_3\times D_5$$C_3\times D_5$$C_3\times C_6$

Other information

Number of subgroups in this autjugacy class$100$
Number of conjugacy classes in this autjugacy class$1$
Möbius function$0$
Projective image$D_5^3.C_3^2:D_6$