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The label of a Maass newform $f \in M_k(\Gamma_0(N), \chi)$ either has the format $N.k.a.m.d$ or $N.m$, where

The shorter form is used when $k=0$ and $a=1$ and $d=1$.

For squarefree level, it is conjectured that there is only one Maass form per eigenvalue $\lambda$, hence $d$ is (currently) always $1$. Generally, there are only finitely many Maass newforms in $M_k(\Gamma_0(N), \chi)$ with the same eigenvalue $\lambda$. Then $d$ denotes the index among these finitely many forms, where the ordering is lexicographical in the sequence $\{ \bigl(\mathrm{Re}(a(n)), \mathrm{Im}(a(n))\bigr) \}_{n \geq 1}$.