Properties

Label 2.0.440.1-32.1-a
Base field \(\Q(\sqrt{-110}) \)
Weight $2$
Level norm $32$
Level \( \left(8, 4 a\right) \)
Dimension $1$
CM $-4$
Base change yes
Sign $+1$
Analytic rank \(0\)

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Base field: \(\Q(\sqrt{-110}) \)

Generator \(a\), with minimal polynomial \(x^2 + 110\); class number \(12\).

Form

Weight: 2
Level: 32.1 = \( \left(8, 4 a\right) \)
Level norm: 32
Dimension: 1
CM: $-4$
Base change: yes 3872.2.a.f , 1600.2.a.n
Newspace:2.0.440.1-32.1 (dimension 60)
Sign of functional equation: $+1$
Analytic rank: \(0\)

Associated elliptic curves

This Bianchi newform is associated to the isogeny class 2.0.440.1-32.1-a of elliptic curves.

Atkin-Lehner eigenvalues

Norm Prime Eigenvalue
\( 2 \) 2.1 = \( \left(2, a\right) \) \( -1 \)

Hecke eigenvalues

The Hecke eigenvalue field is $\Q$. The eigenvalue of the Hecke operator $T_{\mathfrak{p}}$ is $a_{\mathfrak{p}}$. The database contains 25 eigenvalues, of which 20 are currently shown below. We only show the eigenvalues $a_{\mathfrak{p}}$ for primes $\mathfrak{p}$ which do not divide the level.

$N(\mathfrak{p})$ $\mathfrak{p}$ $a_{\mathfrak{p}}$
\( 3 \) 3.1 = \( \left(3, a + 1\right) \) \( 0 \)
\( 3 \) 3.2 = \( \left(3, a + 2\right) \) \( 0 \)
\( 5 \) 5.1 = \( \left(5, a\right) \) \( -2 \)
\( 7 \) 7.1 = \( \left(7, a + 3\right) \) \( 0 \)
\( 7 \) 7.2 = \( \left(7, a + 4\right) \) \( 0 \)
\( 11 \) 11.1 = \( \left(11, a\right) \) \( 0 \)
\( 17 \) 17.1 = \( \left(17, a + 3\right) \) \( -2 \)
\( 17 \) 17.2 = \( \left(17, a + 14\right) \) \( -2 \)
\( 19 \) 19.1 = \( \left(19, a + 2\right) \) \( 0 \)
\( 19 \) 19.2 = \( \left(19, a + 17\right) \) \( 0 \)
\( 29 \) 29.1 = \( \left(29, a + 8\right) \) \( 10 \)
\( 29 \) 29.2 = \( \left(29, a + 21\right) \) \( 10 \)
\( 31 \) 31.1 = \( \left(31, a + 13\right) \) \( 0 \)
\( 31 \) 31.2 = \( \left(31, a + 18\right) \) \( 0 \)
\( 37 \) 37.1 = \( \left(37, a + 1\right) \) \( -2 \)
\( 37 \) 37.2 = \( \left(37, a + 36\right) \) \( -2 \)
\( 53 \) 53.1 = \( \left(53, a + 7\right) \) \( 14 \)
\( 53 \) 53.2 = \( \left(53, a + 46\right) \) \( 14 \)
\( 61 \) 61.1 = \( \left(61, a + 16\right) \) \( 10 \)
\( 61 \) 61.2 = \( \left(61, a + 45\right) \) \( 10 \)
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