Properties

Label 3960.o.165.c1.a1
Order $ 2^{3} \cdot 3 $
Index $ 3 \cdot 5 \cdot 11 $
Normal No

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Subgroup ($H$) information

Description:$C_2\times D_6$
Order: \(24\)\(\medspace = 2^{3} \cdot 3 \)
Index: \(165\)\(\medspace = 3 \cdot 5 \cdot 11 \)
Exponent: \(6\)\(\medspace = 2 \cdot 3 \)
Generators: $\langle(1,3)(4,5)(8,10)(9,11)(12,13), (12,14,13), (12,14), (1,5)(3,4)(6,7)(8,10)(12,13)\rangle$ Copy content Toggle raw display
Derived length: $2$

The subgroup is nonabelian, supersolvable (hence solvable and monomial), hyperelementary for $p = 2$, metabelian, an A-group, and rational.

Ambient group ($G$) information

Description: $S_3\times \PSL(2,11)$
Order: \(3960\)\(\medspace = 2^{3} \cdot 3^{2} \cdot 5 \cdot 11 \)
Exponent: \(330\)\(\medspace = 2 \cdot 3 \cdot 5 \cdot 11 \)
Derived length:$2$

The ambient group is nonabelian, an A-group, and nonsolvable.

Automorphism information

While the subgroup $H$ is not characteristic, the stabilizer $S$ of $H$ in the automorphism group $\operatorname{Aut}(G)$ of the ambient group acts on $H$, yielding a homomorphism $\operatorname{res} : S \to \operatorname{Aut}(H)$. The image of $\operatorname{res}$ on the inner automorphisms $\operatorname{Inn}(G) \cap S$ is the Weyl group $W = N_G(H) / Z_G(H)$.

$\operatorname{Aut}(G)$$S_3\times \PGL(2,11)$, of order \(7920\)\(\medspace = 2^{4} \cdot 3^{2} \cdot 5 \cdot 11 \)
$\operatorname{Aut}(H)$ $S_3\times S_4$, of order \(144\)\(\medspace = 2^{4} \cdot 3^{2} \)
$\operatorname{res}(S)$$S_3^2$, of order \(36\)\(\medspace = 2^{2} \cdot 3^{2} \)
$\card{\operatorname{ker}(\operatorname{res})}$\(4\)\(\medspace = 2^{2} \)
$W$$C_3\times S_3$, of order \(18\)\(\medspace = 2 \cdot 3^{2} \)

Related subgroups

Centralizer:$C_2^2$
Normalizer:$S_3\times A_4$
Normal closure:$S_3\times \PSL(2,11)$
Core:$S_3$
Minimal over-subgroups:$S_3\times A_4$$S_3\times D_6$
Maximal under-subgroups:$D_6$$D_6$$C_2\times C_6$$C_2^3$

Other information

Number of subgroups in this conjugacy class$55$
Möbius function$3$
Projective image$S_3\times \PSL(2,11)$