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Results (22 matches)

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Label Degree Type Faithful Field of Traces $\Q$-character Group Image Image Order Kernel Kernel Order Center
250.6.1a $1$ R \(\Q\) 250.6.1a $C_{25}:C_{10}$ $C_1$ $1$ 1.a1.a1 $250$ 1.a1.a1
250.6.1b $1$ R \(\Q\) 250.6.1b $C_{25}:C_{10}$ $C_2$ $2$ 2.a1.a1 $125$ 1.a1.a1
250.6.1c1 $1$ C \(\Q(\zeta_{5})\) 250.6.1c $C_{25}:C_{10}$ $C_5$ $5$ 5.a1.a1 $50$ 1.a1.a1
250.6.1c2 $1$ C \(\Q(\zeta_{5})\) 250.6.1c $C_{25}:C_{10}$ $C_5$ $5$ 5.a1.a1 $50$ 1.a1.a1
250.6.1c3 $1$ C \(\Q(\zeta_{5})\) 250.6.1c $C_{25}:C_{10}$ $C_5$ $5$ 5.a1.a1 $50$ 1.a1.a1
250.6.1c4 $1$ C \(\Q(\zeta_{5})\) 250.6.1c $C_{25}:C_{10}$ $C_5$ $5$ 5.a1.a1 $50$ 1.a1.a1
250.6.1d1 $1$ C \(\Q(\zeta_{5})\) 250.6.1d $C_{25}:C_{10}$ $C_{10}$ $10$ 10.b1.a1 $25$ 1.a1.a1
250.6.1d2 $1$ C \(\Q(\zeta_{5})\) 250.6.1d $C_{25}:C_{10}$ $C_{10}$ $10$ 10.b1.a1 $25$ 1.a1.a1
250.6.1d3 $1$ C \(\Q(\zeta_{5})\) 250.6.1d $C_{25}:C_{10}$ $C_{10}$ $10$ 10.b1.a1 $25$ 1.a1.a1
250.6.1d4 $1$ C \(\Q(\zeta_{5})\) 250.6.1d $C_{25}:C_{10}$ $C_{10}$ $10$ 10.b1.a1 $25$ 1.a1.a1
250.6.2a1 $2$ R \(\Q(\sqrt{5}) \) 250.6.2a $C_{25}:C_{10}$ $D_5$ $10$ 10.a1.a1 $25$ 10.a1.a1
250.6.2a2 $2$ R \(\Q(\sqrt{5}) \) 250.6.2a $C_{25}:C_{10}$ $D_5$ $10$ 10.a1.a1 $25$ 10.a1.a1
250.6.2b1 $2$ C \(\Q(\zeta_{5})\) 250.6.2b $C_{25}:C_{10}$ $C_5\times D_5$ $50$ 50.a1.a1 $5$ 10.a1.a1
250.6.2b2 $2$ C \(\Q(\zeta_{5})\) 250.6.2b $C_{25}:C_{10}$ $C_5\times D_5$ $50$ 50.a1.a1 $5$ 10.a1.a1
250.6.2b3 $2$ C \(\Q(\zeta_{5})\) 250.6.2b $C_{25}:C_{10}$ $C_5\times D_5$ $50$ 50.a1.a1 $5$ 10.a1.a1
250.6.2b4 $2$ C \(\Q(\zeta_{5})\) 250.6.2b $C_{25}:C_{10}$ $C_5\times D_5$ $50$ 50.a1.a1 $5$ 10.a1.a1
250.6.2c1 $2$ C \(\Q(\zeta_{5})\) 250.6.2c $C_{25}:C_{10}$ $C_5\times D_5$ $50$ 50.a1.a1 $5$ 10.a1.a1
250.6.2c2 $2$ C \(\Q(\zeta_{5})\) 250.6.2c $C_{25}:C_{10}$ $C_5\times D_5$ $50$ 50.a1.a1 $5$ 10.a1.a1
250.6.2c3 $2$ C \(\Q(\zeta_{5})\) 250.6.2c $C_{25}:C_{10}$ $C_5\times D_5$ $50$ 50.a1.a1 $5$ 10.a1.a1
250.6.2c4 $2$ C \(\Q(\zeta_{5})\) 250.6.2c $C_{25}:C_{10}$ $C_5\times D_5$ $50$ 50.a1.a1 $5$ 10.a1.a1
250.6.10a1 $10$ R \(\Q(\sqrt{5}) \) 250.6.10a $C_{25}:C_{10}$ $C_{25}:C_{10}$ $250$ 250.a1.a1 $1$ 250.a1.a1
250.6.10a2 $10$ R \(\Q(\sqrt{5}) \) 250.6.10a $C_{25}:C_{10}$ $C_{25}:C_{10}$ $250$ 250.a1.a1 $1$ 250.a1.a1
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