Let $f$ be an eigenform normalized so that $a_{(1)} = 1$. The Hecke operator $T_\frak{n}$ acts by $T_\frak{n}f = a_\frak{n}f$ where $a_\frak{n}$ is the Hecke eigenvalue.
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- Last edited by Benjamin Breen on 2019-10-04 15:46:52
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Not referenced anywhere at the moment.