show · mf.hilbert.eigenvalue all knowls · up · search:

Let $f$ be an eigenform normalized so that $a_{(1)} = 1$. The Hecke operator $T_\frak{n}$ acts by $T_\frak{n}f = a_\frak{n}f$ where $a_\frak{n}$ is the Hecke eigenvalue.

Knowl status:
  • Review status: beta
  • Last edited by Benjamin Breen on 2019-10-04 15:46:52
Referred to by:

Not referenced anywhere at the moment.

History: (expand/hide all)