The sign of an L-function is the complex number $\varepsilon$ occurring in its functional equation
\[ \Lambda(s) := N^{s/2} \prod_{j=1}^J \Gamma_{\mathbb R}(s+\mu_j) \prod_{k=1}^K \Gamma_{\mathbb C}(s+\nu_k) \cdot L(s) = \varepsilon \overline{\Lambda}(1-s). \]
It appears as the fourth component of the Selberg data of L.
If all of the coefficients of the Dirichlet series defining $L(s)$ are real, then necessarily $ \varepsilon = \pm 1 $. If the coefficients are real and $ \varepsilon = - 1 $, then $ L(1/2)=0 $.
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- Last edited by David Farmer on 2012-06-29 08:10:51
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- 2012-06-29 08:10:51 by David Farmer (Reviewed)