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Let

• $K$ be a finite Galois extension of $\Q_p$ for some prime $p$,
• $\mathcal{O}_K$ the ring of integers for $K$,
• $P$ the unique maximal ideal of $\mathcal{O}_K$, and
• $k=\mathcal{O}_K/P$.

Then each $\sigma\in \Gal(K/\Q_p)$ induces a element of $\Gal(k/\F_p)$. The kernel of the resulting homomorphism $\Gal(K/\Q_p) \to \Gal(k/\F_p)$ is the inertia group of $K$.

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• Review status: reviewed
• Last edited by John Jones on 2018-07-04 23:25:09
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