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If $G$ is a group, its inner automorphism group is a normal subgroup of the full automorphism group. Then, the outer automorphism group of $G$ is \[ \mathrm{Out}(G) = \Aut(G)/\mathrm{Inn}(G).\]

Knowl status:
  • Review status: beta
  • Last edited by John Jones on 2019-05-23 23:32:21
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