Properties

Label 1200.481.300.c1.a1
Order $ 2^{2} $
Index $ 2^{2} \cdot 3 \cdot 5^{2} $
Normal No

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Subgroup ($H$) information

Description:$C_4$
Order: \(4\)\(\medspace = 2^{2} \)
Index: \(300\)\(\medspace = 2^{2} \cdot 3 \cdot 5^{2} \)
Exponent: \(4\)\(\medspace = 2^{2} \)
Generators: $\left(\begin{array}{rrrr} 4 & 0 & 0 & 0 \\ 0 & 4 & 0 & 0 \\ 0 & 0 & 4 & 0 \\ 0 & 0 & 0 & 4 \end{array}\right), \left(\begin{array}{rrrr} 0 & 3 & 3 & 2 \\ 3 & 4 & 1 & 2 \\ 1 & 2 & 0 & 4 \\ 1 & 1 & 1 & 1 \end{array}\right)$ Copy content Toggle raw display
Nilpotency class: $1$
Derived length: $1$

The subgroup is cyclic (hence abelian, nilpotent, solvable, supersolvable, monomial, elementary, hyperelementary, metacyclic, metabelian, a Z-group, and an A-group) and a $p$-group.

Ambient group ($G$) information

Description: $\SL(2,5):D_5$
Order: \(1200\)\(\medspace = 2^{4} \cdot 3 \cdot 5^{2} \)
Exponent: \(60\)\(\medspace = 2^{2} \cdot 3 \cdot 5 \)
Derived length:$2$

The ambient group is nonabelian and nonsolvable.

Automorphism information

While the subgroup $H$ is not characteristic, the stabilizer $S$ of $H$ in the automorphism group $\operatorname{Aut}(G)$ of the ambient group acts on $H$, yielding a homomorphism $\operatorname{res} : S \to \operatorname{Aut}(H)$. The image of $\operatorname{res}$ on the inner automorphisms $\operatorname{Inn}(G) \cap S$ is the Weyl group $W = N_G(H) / Z_G(H)$.

$\operatorname{Aut}(G)$$C_2\times F_5\times S_5$, of order \(4800\)\(\medspace = 2^{6} \cdot 3 \cdot 5^{2} \)
$\operatorname{Aut}(H)$ $C_2$, of order \(2\)
$\operatorname{res}(S)$$C_2$, of order \(2\)
$\card{\operatorname{ker}(\operatorname{res})}$\(160\)\(\medspace = 2^{5} \cdot 5 \)
$W$$C_2$, of order \(2\)

Related subgroups

Centralizer:$C_4\times D_5$
Normalizer:$D_{20}:C_2$
Normal closure:$\SL(2,5)$
Core:$C_2$
Minimal over-subgroups:$C_{20}$$C_5:C_4$$C_3:C_4$$C_2\times C_4$$D_4$$Q_8$
Maximal under-subgroups:$C_2$

Other information

Number of subgroups in this conjugacy class$15$
Möbius function$20$
Projective image$D_5\times A_5$