magma: G := TransitiveGroup(5, 2);
Degree $n$: | | $5$ |
magma: t, n := TransitiveGroupIdentification(G); n;
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Transitive number $t$: | | $2$ |
magma: t, n := TransitiveGroupIdentification(G); t;
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Group: | | $D_{5}$ |
CHM label: | |
$D(5) = 5:2$
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Parity: | | $1$
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Primitive: | | yes |
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magma: NilpotencyClass(G);
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$\card{\Aut(F/K)}$: | | $1$ |
magma: Order(Centralizer(SymmetricGroup(n), G));
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Generators: | | (1,2,3,4,5), (1,4)(2,3)
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Resolvents shown for degrees $\leq 47$
Prime degree - none
10T2Siblings are shown with degree $\leq 47$
A number field with this Galois group has no arithmetically equivalent fields.
Label | Cycle Type | Size | Order | Index | Representative |
1A |
$1^{5}$ |
$1$ |
$1$ |
$0$ |
$()$ |
2A |
$2^{2},1$ |
$5$ |
$2$ |
$2$ |
$(2,5)(3,4)$ |
5A1 |
$5$ |
$2$ |
$5$ |
$4$ |
$(1,2,3,4,5)$ |
5A2 |
$5$ |
$2$ |
$5$ |
$4$ |
$(1,3,5,2,4)$ |
Malle's constant $a(G)$:
$1/2$
magma: ConjugacyClasses(G);
magma: CharacterTable(G);
Complete
list of indecomposable integral representations:
Name | Dim |
$(1,2,3,4,5) \mapsto $ |
$(2,5)(3,4) \mapsto $ |
Triv | $1$ |
$\left(\begin{array}{r}1\end{array}\right)$ |
$\left(\begin{array}{r}1\end{array}\right)$ |
Sign | $1$ |
$\left(\begin{array}{r}1\end{array}\right)$ |
$\left(\begin{array}{r}-1\end{array}\right)$ |
$L$ | $2$ |
$\left(\begin{array}{rr}1 & 0\\0 & 1\end{array}\right)$ |
$\left(\begin{array}{rr}0 & 1\\1 & 0\end{array}\right)$ |
$A$ | $4$ |
$\left(\begin{array}{rrrr}0 & 1 & 0 & 0\\0 & 0 & 1 & 0\\0 & 0 & 0 & 1\\-1 & -1 & -1 & -1\end{array}\right)$ |
$\left(\begin{array}{rrrr}1 & 0 & 0 & 0\\-1 & -1 & -1 & -1\\0 & 0 & 0 & 1\\0 & 0 & 1 & 0\end{array}\right)$ |
$A'$ | $4$ |
$\left(\begin{array}{rrrr}0 & 1 & 0 & 0\\0 & 0 & 1 & 0\\0 & 0 & 0 & 1\\-1 & -1 & -1 & -1\end{array}\right)$ |
$\left(\begin{array}{rrrr}-1 & 0 & 0 & 0\\1 & 1 & 1 & 1\\0 & 0 & 0 & -1\\0 & 0 & -1 & 0\end{array}\right)$ |
$(A,\textrm{Sign})$ | $5$ |
$\left(\begin{array}{rrrrr}0 & 1 & 0 & 0 & 0\\0 & 0 & 1 & 0 & 0\\0 & 0 & 0 & 1 & 0\\-1 & -1 & -1 & -1 & 0\\1 & 0 & 0 & 0 & 1\end{array}\right)$ |
$\left(\begin{array}{rrrrr}1 & 0 & 0 & 0 & 0\\-1 & -1 & -1 & -1 & 0\\0 & 0 & 0 & 1 & 0\\0 & 0 & 1 & 0 & 0\\-1 & 0 & 0 & 0 & -1\end{array}\right)$ |
$(A',\textrm{Triv})$ | $5$ |
$\left(\begin{array}{rrrrr}0 & 1 & 0 & 0 & 0\\0 & 0 & 1 & 0 & 0\\0 & 0 & 0 & 1 & 0\\-1 & -1 & -1 & -1 & 0\\1 & 0 & 0 & 0 & 1\end{array}\right)$ |
$\left(\begin{array}{rrrrr}-1 & 0 & 0 & 0 & 0\\1 & 1 & 1 & 1 & 0\\0 & 0 & 0 & -1 & 0\\0 & 0 & -1 & 0 & 0\\1 & 0 & 0 & 0 & 1\end{array}\right)$ |
$(A,L)$ | $6$ |
$\left(\begin{array}{rrrrrr}0 & 1 & 0 & 0 & 0 & 0\\0 & 0 & 1 & 0 & 0 & 0\\0 & 0 & 0 & 1 & 0 & 0\\-1 & -1 & -1 & -1 & 0 & 0\\-1 & 0 & 0 & 0 & 1 & 0\\1 & 0 & 0 & 0 & 0 & 1\end{array}\right)$ |
$\left(\begin{array}{rrrrrr}1 & 0 & 0 & 0 & 0 & 0\\-1 & -1 & -1 & -1 & 0 & 0\\0 & 0 & 0 & 1 & 0 & 0\\0 & 0 & 1 & 0 & 0 & 0\\1 & 0 & 0 & 0 & 0 & 1\\-1 & 0 & 0 & 0 & 1 & 0\end{array}\right)$ |
$(A',L)$ | $6$ |
$\left(\begin{array}{rrrrrr}0 & 1 & 0 & 0 & 0 & 0\\0 & 0 & 1 & 0 & 0 & 0\\0 & 0 & 0 & 1 & 0 & 0\\-1 & -1 & -1 & -1 & 0 & 0\\1 & 0 & 0 & 0 & 1 & 0\\1 & 0 & 0 & 0 & 0 & 1\end{array}\right)$ |
$\left(\begin{array}{rrrrrr}-1 & 0 & 0 & 0 & 0 & 0\\1 & 1 & 1 & 1 & 0 & 0\\0 & 0 & 0 & -1 & 0 & 0\\0 & 0 & -1 & 0 & 0 & 0\\1 & 0 & 0 & 0 & 0 & 1\\1 & 0 & 0 & 0 & 1 & 0\end{array}\right)$ |
$(A+A',L)$ | $10$ |
$\left(\begin{array}{rrrrrrrrrr}0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 0 & 0 & 1 & 0 & 0\\0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 1\\0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 1 & 0\\0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0\end{array}\right)$ |
$\left(\begin{array}{rrrrrrrrrr}0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 1 & 0\\0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 1\\1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 0 & 0 & 1 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0\\0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0\end{array}\right)$ |
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The decomposition of an arbitrary integral representation as a direct
sum of indecomposables is not unique, in general. It
is unique up to the following isomorphisms: