magma:G := TransitiveGroup(5, 2);
sage:G = TransitiveGroup(5, 2)
oscar:G = transitive_group(5, 2)
gap:G := TransitiveGroup(5, 2);
| Abstract group: | | $D_{5}$ |
magma:IdentifyGroup(G);
sage:G.id()
oscar:small_group_identification(G)
gap:IdGroup(G);
|
| Order: | | $10=2 \cdot 5$ |
magma:Order(G);
sage:G.order()
oscar:order(G)
gap:Order(G);
|
| Cyclic: | | no |
magma:IsCyclic(G);
sage:G.is_cyclic()
oscar:is_cyclic(G)
gap:IsCyclic(G);
|
| Abelian: | | no |
magma:IsAbelian(G);
sage:G.is_abelian()
oscar:is_abelian(G)
gap:IsAbelian(G);
|
| Solvable: | | yes |
magma:IsSolvable(G);
sage:G.is_solvable()
oscar:is_solvable(G)
gap:IsSolvable(G);
|
| Nilpotency class: | | not nilpotent |
magma:NilpotencyClass(G);
sage:libgap(G).NilpotencyClassOfGroup() if G.is_nilpotent() else -1
oscar:if is_nilpotent(G) nilpotency_class(G) end
gap:if IsNilpotentGroup(G) then NilpotencyClassOfGroup(G); fi;
|
| Degree $n$: | | $5$ |
magma:t, n := TransitiveGroupIdentification(G); n;
sage:G.degree()
oscar:degree(G)
gap:NrMovedPoints(G);
|
| Transitive number $t$: | | $2$ |
magma:t, n := TransitiveGroupIdentification(G); t;
sage:G.transitive_number()
oscar:transitive_group_identification(G)[2]
gap:TransitiveIdentification(G);
|
| CHM label: | |
$D(5) = 5:2$
|
| Parity: | | $1$ |
magma:IsEven(G);
sage:all(g.SignPerm() == 1 for g in libgap(G).GeneratorsOfGroup())
oscar:is_even(G)
gap:ForAll(GeneratorsOfGroup(G), g -> SignPerm(g) = 1);
|
| Transitivity: | | 1 |
| Primitive: | | yes |
magma:IsPrimitive(G);
sage:G.is_primitive()
oscar:is_primitive(G)
gap:IsPrimitive(G);
|
| $\card{\Aut(F/K)}$: | | $1$ |
magma:Order(Centralizer(SymmetricGroup(n), G));
sage:SymmetricGroup(5).centralizer(G).order()
oscar:order(centralizer(symmetric_group(5), G)[1])
gap:Order(Centralizer(SymmetricGroup(5), G));
|
| Generators: | | $(1,2,3,4,5)$, $(1,4)(2,3)$ |
magma:Generators(G);
sage:G.gens()
oscar:gens(G)
gap:GeneratorsOfGroup(G);
|
Resolvents shown for degrees $\leq 47$
Prime degree - none
10T2Siblings are shown with degree $\leq 47$
A number field with this Galois group has no arithmetically equivalent fields.
| Label | Cycle Type | Size | Order | Index | Representative |
| 1A |
$1^{5}$ |
$1$ |
$1$ |
$0$ |
$()$ |
| 2A |
$2^{2},1$ |
$5$ |
$2$ |
$2$ |
$(1,4)(2,3)$ |
| 5A1 |
$5$ |
$2$ |
$5$ |
$4$ |
$(1,2,3,4,5)$ |
| 5A2 |
$5$ |
$2$ |
$5$ |
$4$ |
$(1,3,5,2,4)$ |
Malle's constant $a(G)$:
$1/2$
magma:ConjugacyClasses(G);
sage:G.conjugacy_classes()
oscar:conjugacy_classes(G)
gap:ConjugacyClasses(G);
magma:CharacterTable(G);
sage:G.character_table()
oscar:character_table(G)
gap:CharacterTable(G);
|
Complete
list of indecomposable integral representations:
| Name | Dim |
$(1,2,3,4,5) \mapsto $ |
$(2,5)(3,4) \mapsto $ |
| Triv | $1$ |
$\left(\begin{array}{r}1\end{array}\right)$ |
$\left(\begin{array}{r}1\end{array}\right)$ |
| Sign | $1$ |
$\left(\begin{array}{r}1\end{array}\right)$ |
$\left(\begin{array}{r}-1\end{array}\right)$ |
| $L$ | $2$ |
$\left(\begin{array}{rr}1 & 0\\0 & 1\end{array}\right)$ |
$\left(\begin{array}{rr}0 & 1\\1 & 0\end{array}\right)$ |
| $A$ | $4$ |
$\left(\begin{array}{rrrr}0 & 1 & 0 & 0\\0 & 0 & 1 & 0\\0 & 0 & 0 & 1\\-1 & -1 & -1 & -1\end{array}\right)$ |
$\left(\begin{array}{rrrr}1 & 0 & 0 & 0\\-1 & -1 & -1 & -1\\0 & 0 & 0 & 1\\0 & 0 & 1 & 0\end{array}\right)$ |
| $A'$ | $4$ |
$\left(\begin{array}{rrrr}0 & 1 & 0 & 0\\0 & 0 & 1 & 0\\0 & 0 & 0 & 1\\-1 & -1 & -1 & -1\end{array}\right)$ |
$\left(\begin{array}{rrrr}-1 & 0 & 0 & 0\\1 & 1 & 1 & 1\\0 & 0 & 0 & -1\\0 & 0 & -1 & 0\end{array}\right)$ |
| $(A,\textrm{Sign})$ | $5$ |
$\left(\begin{array}{rrrrr}0 & 1 & 0 & 0 & 0\\0 & 0 & 1 & 0 & 0\\0 & 0 & 0 & 1 & 0\\-1 & -1 & -1 & -1 & 0\\1 & 0 & 0 & 0 & 1\end{array}\right)$ |
$\left(\begin{array}{rrrrr}1 & 0 & 0 & 0 & 0\\-1 & -1 & -1 & -1 & 0\\0 & 0 & 0 & 1 & 0\\0 & 0 & 1 & 0 & 0\\-1 & 0 & 0 & 0 & -1\end{array}\right)$ |
| $(A',\textrm{Triv})$ | $5$ |
$\left(\begin{array}{rrrrr}0 & 1 & 0 & 0 & 0\\0 & 0 & 1 & 0 & 0\\0 & 0 & 0 & 1 & 0\\-1 & -1 & -1 & -1 & 0\\1 & 0 & 0 & 0 & 1\end{array}\right)$ |
$\left(\begin{array}{rrrrr}-1 & 0 & 0 & 0 & 0\\1 & 1 & 1 & 1 & 0\\0 & 0 & 0 & -1 & 0\\0 & 0 & -1 & 0 & 0\\1 & 0 & 0 & 0 & 1\end{array}\right)$ |
| $(A,L)$ | $6$ |
$\left(\begin{array}{rrrrrr}0 & 1 & 0 & 0 & 0 & 0\\0 & 0 & 1 & 0 & 0 & 0\\0 & 0 & 0 & 1 & 0 & 0\\-1 & -1 & -1 & -1 & 0 & 0\\-1 & 0 & 0 & 0 & 1 & 0\\1 & 0 & 0 & 0 & 0 & 1\end{array}\right)$ |
$\left(\begin{array}{rrrrrr}1 & 0 & 0 & 0 & 0 & 0\\-1 & -1 & -1 & -1 & 0 & 0\\0 & 0 & 0 & 1 & 0 & 0\\0 & 0 & 1 & 0 & 0 & 0\\1 & 0 & 0 & 0 & 0 & 1\\-1 & 0 & 0 & 0 & 1 & 0\end{array}\right)$ |
| $(A',L)$ | $6$ |
$\left(\begin{array}{rrrrrr}0 & 1 & 0 & 0 & 0 & 0\\0 & 0 & 1 & 0 & 0 & 0\\0 & 0 & 0 & 1 & 0 & 0\\-1 & -1 & -1 & -1 & 0 & 0\\1 & 0 & 0 & 0 & 1 & 0\\1 & 0 & 0 & 0 & 0 & 1\end{array}\right)$ |
$\left(\begin{array}{rrrrrr}-1 & 0 & 0 & 0 & 0 & 0\\1 & 1 & 1 & 1 & 0 & 0\\0 & 0 & 0 & -1 & 0 & 0\\0 & 0 & -1 & 0 & 0 & 0\\1 & 0 & 0 & 0 & 0 & 1\\1 & 0 & 0 & 0 & 1 & 0\end{array}\right)$ |
| $(A+A',L)$ | $10$ |
$\left(\begin{array}{rrrrrrrrrr}0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 0 & 0 & 1 & 0 & 0\\0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 1\\0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 1 & 0\\0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0\end{array}\right)$ |
$\left(\begin{array}{rrrrrrrrrr}0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 1 & 0\\0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 1\\1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 0 & 0 & 1 & 0 & 0\\0 & 0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0\\0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0\end{array}\right)$ |
|
The decomposition of an arbitrary integral representation as a direct
sum of indecomposables is not unique, in general. It
is unique up to the following isomorphisms:
| $f_{ 1 } =$ |
$x^{5} + \left(t − 3\right) x^{4} + \left(s − t + 3\right) x^{3} +\left(t^{2} − t − 2 s − 1\right) x^{2} + s x + t$
|
| The polynomial $f_{1}$ is generic for any base field $K$ |