Learn more

Refine search


Results (5 matches)

  displayed columns for results
Label Class Base field Conductor norm Rank Torsion CM Sato-Tate Regulator Period Leading coeff j-invariant Weierstrass coefficients Weierstrass equation
4464.1-a1 4464.1-a \(\Q(\sqrt{-3}) \) \( 2^{4} \cdot 3^{2} \cdot 31 \) 0 $\Z/2\Z$ $\mathrm{SU}(2)$ $1$ $1.360678882$ 1.571176638 \( -\frac{355344}{961} a + \frac{669360}{961} \) \( \bigl[0\) , \( 0\) , \( 0\) , \( -12 a + 21\) , \( -24 a + 50\bigr] \) ${y}^2={x}^{3}+\left(-12a+21\right){x}-24a+50$
71424.1-b1 71424.1-b \(\Q(\sqrt{-3}) \) \( 2^{8} \cdot 3^{2} \cdot 31 \) $1$ $\Z/2\Z$ $\mathrm{SU}(2)$ $0.296057380$ $2.356764957$ 3.222712205 \( -\frac{355344}{961} a + \frac{669360}{961} \) \( \bigl[0\) , \( a + 1\) , \( 0\) , \( 4 a + 4\) , \( 12 a\bigr] \) ${y}^2={x}^{3}+\left(a+1\right){x}^{2}+\left(4a+4\right){x}+12a$
71424.1-c1 71424.1-c \(\Q(\sqrt{-3}) \) \( 2^{8} \cdot 3^{2} \cdot 31 \) $1$ $\Z/2\Z$ $\mathrm{SU}(2)$ $0.540606015$ $1.360678882$ 3.397550170 \( -\frac{355344}{961} a + \frac{669360}{961} \) \( \bigl[0\) , \( 0\) , \( 0\) , \( 21 a - 9\) , \( 24 a - 50\bigr] \) ${y}^2={x}^{3}+\left(21a-9\right){x}+24a-50$
71424.1-e1 71424.1-e \(\Q(\sqrt{-3}) \) \( 2^{8} \cdot 3^{2} \cdot 31 \) 0 $\Z/2\Z$ $\mathrm{SU}(2)$ $1$ $2.356764957$ 2.721357765 \( -\frac{355344}{961} a + \frac{669360}{961} \) \( \bigl[0\) , \( -a - 1\) , \( 0\) , \( 4 a + 4\) , \( -12 a\bigr] \) ${y}^2={x}^{3}+\left(-a-1\right){x}^{2}+\left(4a+4\right){x}-12a$
138384.1-b1 138384.1-b \(\Q(\sqrt{-3}) \) \( 2^{4} \cdot 3^{2} \cdot 31^{2} \) 0 $\Z/2\Z$ $\mathrm{SU}(2)$ $1$ $0.423287482$ 2.932621700 \( -\frac{355344}{961} a + \frac{669360}{961} \) \( \bigl[0\) , \( -a - 1\) , \( 0\) , \( 150 a + 63\) , \( -1781 a + 813\bigr] \) ${y}^2={x}^{3}+\left(-a-1\right){x}^{2}+\left(150a+63\right){x}-1781a+813$
  displayed columns for results

  *The rank, regulator and analytic order of Ш are not known for all curves in the database; curves for which these are unknown will not appear in searches specifying one of these quantities.