Basic invariants
Galois action
Roots of defining polynomial
The roots of $f$ are computed in an extension of $\Q_{ 11 }$ to precision 5.
Minimal polynomial of a generator $a$ of $K$ over $\mathbb{Q}_{ 11 }$: $ x^{3} + 2 x + 9 $
Roots:
| $r_{ 1 }$ |
$=$ |
$ 2 a + 2 + \left(6 a^{2} + 10 a + 8\right)\cdot 11 + \left(10 a^{2} + 4 a\right)\cdot 11^{2} + \left(2 a + 7\right)\cdot 11^{3} + \left(3 a^{2} + 9 a + 4\right)\cdot 11^{4} +O\left(11^{ 5 }\right)$ |
| $r_{ 2 }$ |
$=$ |
$ 8 a^{2} + 9 a + 1 + \left(3 a^{2} + 8\right)\cdot 11 + \left(5 a^{2} + 10 a + 9\right)\cdot 11^{2} + \left(3 a^{2} + 10 a\right)\cdot 11^{3} + \left(7 a^{2} + 3 a\right)\cdot 11^{4} +O\left(11^{ 5 }\right)$ |
| $r_{ 3 }$ |
$=$ |
$ 9 a^{2} + 7 a + 3 + \left(6 a + 1\right)\cdot 11 + \left(2 a^{2} + 5 a + 4\right)\cdot 11^{2} + \left(10 a^{2} + 2 a + 8\right)\cdot 11^{3} + \left(4 a^{2} + 8 a + 10\right)\cdot 11^{4} +O\left(11^{ 5 }\right)$ |
| $r_{ 4 }$ |
$=$ |
$ 4 a^{2} + 7 a + 3 + \left(a^{2} + 2 a + 1\right)\cdot 11 + \left(7 a^{2} + 3 a + 1\right)\cdot 11^{2} + \left(2 a^{2} + 6 a + 7\right)\cdot 11^{3} + \left(6 a^{2} + 4 a + 9\right)\cdot 11^{4} +O\left(11^{ 5 }\right)$ |
| $r_{ 5 }$ |
$=$ |
$ 2 a^{2} + 2 a + 1 + \left(4 a^{2} + 5 a + 2\right)\cdot 11 + \left(9 a^{2} + 10\right)\cdot 11^{2} + \left(10 a^{2} + 6 a + 1\right)\cdot 11^{3} + \left(2 a^{2} + 4 a + 8\right)\cdot 11^{4} +O\left(11^{ 5 }\right)$ |
| $r_{ 6 }$ |
$=$ |
$ 10 a^{2} + 6 a + \left(5 a^{2} + 7 a\right)\cdot 11 + \left(9 a^{2} + 8 a + 8\right)\cdot 11^{2} + \left(4 a^{2} + 4 a + 2\right)\cdot 11^{3} + \left(8 a^{2} + 2 a + 5\right)\cdot 11^{4} +O\left(11^{ 5 }\right)$ |
| $r_{ 7 }$ |
$=$ |
$ 3 + 11 + 10\cdot 11^{2} + 4\cdot 11^{3} + 5\cdot 11^{4} +O\left(11^{ 5 }\right)$ |
Generators of the action on the roots
$r_1, \ldots, r_{ 7 }$
| Cycle notation |
| $(1,5,6,4)(3,7)$ |
| $(1,2)(5,7)$ |
Character values on conjugacy classes
| Size | Order | Action on
$r_1, \ldots, r_{ 7 }$
| Character value |
| $1$ | $1$ | $()$ | $7$ |
| $21$ | $2$ | $(1,2)(5,7)$ | $-1$ |
| $56$ | $3$ | $(1,3,6)(2,5,4)$ | $1$ |
| $42$ | $4$ | $(1,5,6,4)(3,7)$ | $-1$ |
| $24$ | $7$ | $(1,7,3,5,6,4,2)$ | $0$ |
| $24$ | $7$ | $(1,5,2,3,4,7,6)$ | $0$ |
The blue line marks the conjugacy class containing complex conjugation.
