Basic invariants
Galois action
Roots of defining polynomial
The roots of $f$ are computed in an extension of $\Q_{ 17 }$ to precision 7.
Minimal polynomial of a generator $a$ of $K$ over $\mathbb{Q}_{ 17 }$: $ x^{2} + 16 x + 3 $
Roots:
| $r_{ 1 }$ |
$=$ |
$ 14 + 6\cdot 17 + 11\cdot 17^{2} + 5\cdot 17^{3} + 17^{4} + 2\cdot 17^{5} + 17^{6} +O\left(17^{ 7 }\right)$ |
| $r_{ 2 }$ |
$=$ |
$ 8 a + 10 + \left(9 a + 13\right)\cdot 17 + \left(11 a + 7\right)\cdot 17^{2} + \left(8 a + 7\right)\cdot 17^{3} + \left(12 a + 10\right)\cdot 17^{4} + \left(5 a + 2\right)\cdot 17^{5} + \left(12 a + 4\right)\cdot 17^{6} +O\left(17^{ 7 }\right)$ |
| $r_{ 3 }$ |
$=$ |
$ a + 10 + \left(2 a + 2\right)\cdot 17 + \left(a + 9\right)\cdot 17^{2} + \left(7 a + 9\right)\cdot 17^{3} + \left(3 a + 8\right)\cdot 17^{4} + \left(4 a + 8\right)\cdot 17^{5} + \left(9 a + 7\right)\cdot 17^{6} +O\left(17^{ 7 }\right)$ |
| $r_{ 4 }$ |
$=$ |
$ 7 + 9\cdot 17 + 4\cdot 17^{2} + 8\cdot 17^{3} + 11\cdot 17^{4} + 15\cdot 17^{5} + 14\cdot 17^{6} +O\left(17^{ 7 }\right)$ |
| $r_{ 5 }$ |
$=$ |
$ 9 a + 1 + \left(7 a + 15\right)\cdot 17 + \left(5 a + 9\right)\cdot 17^{2} + \left(8 a + 4\right)\cdot 17^{3} + \left(4 a + 14\right)\cdot 17^{4} + \left(11 a + 12\right)\cdot 17^{5} + \left(4 a + 10\right)\cdot 17^{6} +O\left(17^{ 7 }\right)$ |
| $r_{ 6 }$ |
$=$ |
$ 16 a + 11 + \left(14 a + 3\right)\cdot 17 + \left(15 a + 8\right)\cdot 17^{2} + \left(9 a + 15\right)\cdot 17^{3} + \left(13 a + 4\right)\cdot 17^{4} + \left(12 a + 9\right)\cdot 17^{5} + \left(7 a + 12\right)\cdot 17^{6} +O\left(17^{ 7 }\right)$ |
Generators of the action on the roots
$r_1, \ldots, r_{ 6 }$
| Cycle notation |
| $(1,5)(3,6)$ |
| $(3,6,4)$ |
| $(1,3,2,4,5,6)$ |
| $(1,2,5)(3,4,6)$ |
| $(2,5)(4,6)$ |
Character values on conjugacy classes
| Size | Order | Action on
$r_1, \ldots, r_{ 6 }$
| Character value |
| $1$ | $1$ | $()$ | $4$ |
| $3$ | $2$ | $(1,4)(2,6)(3,5)$ | $0$ |
| $3$ | $2$ | $(1,3)(2,6)(4,5)$ | $0$ |
| $9$ | $2$ | $(1,5)(3,6)$ | $0$ |
| $2$ | $3$ | $(1,2,5)(3,4,6)$ | $-2$ |
| $2$ | $3$ | $(1,2,5)(3,6,4)$ | $-2$ |
| $4$ | $3$ | $(3,6,4)$ | $1$ |
| $6$ | $6$ | $(1,3,2,4,5,6)$ | $0$ |
| $6$ | $6$ | $(1,4,2,3,5,6)$ | $0$ |
The blue line marks the conjugacy class containing complex conjugation.
