Basic invariants
| Dimension: | $4$ |
| Group: | $C_3^2:D_4$ |
| Conductor: | \(19197\)\(\medspace = 3^{5} \cdot 79 \) |
| Frobenius-Schur indicator: | $1$ |
| Root number: | $1$ |
| Artin number field: | Galois closure of 6.0.57591.1 |
| Galois orbit size: | $1$ |
| Smallest permutation container: | $C_3^2:D_4$ |
| Parity: | even |
| Projective image: | $\SOPlus(4,2)$ |
| Projective field: | Galois closure of 6.0.57591.1 |
Galois action
Roots of defining polynomial
The roots of $f$ are computed in an extension of $\Q_{ 31 }$ to precision 5.
Minimal polynomial of a generator $a$ of $K$ over $\mathbb{Q}_{ 31 }$:
\( x^{2} + 29x + 3 \)
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Roots:
| $r_{ 1 }$ | $=$ |
\( 27 + 20\cdot 31 + 29\cdot 31^{2} + 10\cdot 31^{3} + 16\cdot 31^{4} +O(31^{5})\)
| $r_{ 2 }$ |
$=$ |
\( 24 a + 9 + \left(28 a + 19\right)\cdot 31 + \left(12 a + 17\right)\cdot 31^{2} + \left(6 a + 25\right)\cdot 31^{3} + \left(16 a + 9\right)\cdot 31^{4} +O(31^{5})\)
| $r_{ 3 }$ |
$=$ |
\( 16 + 31 + 8\cdot 31^{2} + 10\cdot 31^{3} + 19\cdot 31^{4} +O(31^{5})\)
| $r_{ 4 }$ |
$=$ |
\( 6 a + 17 + \left(8 a + 9\right)\cdot 31 + 15 a\cdot 31^{2} + \left(28 a + 5\right)\cdot 31^{3} + \left(5 a + 14\right)\cdot 31^{4} +O(31^{5})\)
| $r_{ 5 }$ |
$=$ |
\( 7 a + 26 + \left(2 a + 21\right)\cdot 31 + \left(18 a + 14\right)\cdot 31^{2} + \left(24 a + 25\right)\cdot 31^{3} + \left(14 a + 4\right)\cdot 31^{4} +O(31^{5})\)
| $r_{ 6 }$ |
$=$ |
\( 25 a + 29 + \left(22 a + 19\right)\cdot 31 + \left(15 a + 22\right)\cdot 31^{2} + \left(2 a + 15\right)\cdot 31^{3} + \left(25 a + 28\right)\cdot 31^{4} +O(31^{5})\)
| |
Generators of the action on the roots $r_1, \ldots, r_{ 6 }$
| Cycle notation |
Character values on conjugacy classes
| Size | Order | Action on $r_1, \ldots, r_{ 6 }$ | Character values |
| $c1$ | |||
| $1$ | $1$ | $()$ | $4$ |
| $6$ | $2$ | $(1,3)(2,4)(5,6)$ | $0$ |
| $6$ | $2$ | $(2,5)$ | $2$ |
| $9$ | $2$ | $(2,5)(4,6)$ | $0$ |
| $4$ | $3$ | $(1,2,5)$ | $1$ |
| $4$ | $3$ | $(1,2,5)(3,4,6)$ | $-2$ |
| $18$ | $4$ | $(1,3)(2,6,5,4)$ | $0$ |
| $12$ | $6$ | $(1,4,2,6,5,3)$ | $0$ |
| $12$ | $6$ | $(2,5)(3,4,6)$ | $-1$ |