Basic invariants
Galois action
Roots of defining polynomial
The roots of $f$ are computed in $\Q_{ 31 }$ to precision 6.
Roots:
| $r_{ 1 }$ |
$=$ |
$ 11 + 18\cdot 31 + 16\cdot 31^{2} + 8\cdot 31^{3} + 4\cdot 31^{4} + 27\cdot 31^{5} +O\left(31^{ 6 }\right)$ |
| $r_{ 2 }$ |
$=$ |
$ 17 + 30\cdot 31 + 22\cdot 31^{2} + 13\cdot 31^{3} + 23\cdot 31^{4} + 8\cdot 31^{5} +O\left(31^{ 6 }\right)$ |
| $r_{ 3 }$ |
$=$ |
$ 18 + 20\cdot 31 + 19\cdot 31^{2} + 4\cdot 31^{3} + 8\cdot 31^{4} + 19\cdot 31^{5} +O\left(31^{ 6 }\right)$ |
| $r_{ 4 }$ |
$=$ |
$ 20 + 22\cdot 31 + 16\cdot 31^{2} + 11\cdot 31^{3} + 31^{4} + 24\cdot 31^{5} +O\left(31^{ 6 }\right)$ |
| $r_{ 5 }$ |
$=$ |
$ 27 + 17\cdot 31^{2} + 23\cdot 31^{3} + 24\cdot 31^{4} + 13\cdot 31^{5} +O\left(31^{ 6 }\right)$ |
Generators of the action on the roots
$r_1, \ldots, r_{ 5 }$
| Cycle notation |
| $(1,2,5,3,4)$ |
Character values on conjugacy classes
| Size | Order | Action on
$r_1, \ldots, r_{ 5 }$
| Character value |
| $1$ | $1$ | $()$ | $1$ |
| $1$ | $5$ | $(1,2,5,3,4)$ | $\zeta_{5}$ |
| $1$ | $5$ | $(1,5,4,2,3)$ | $\zeta_{5}^{2}$ |
| $1$ | $5$ | $(1,3,2,4,5)$ | $\zeta_{5}^{3}$ |
| $1$ | $5$ | $(1,4,3,5,2)$ | $-\zeta_{5}^{3} - \zeta_{5}^{2} - \zeta_{5} - 1$ |
The blue line marks the conjugacy class containing complex conjugation.
