If \(f\) is a Maass form with Laplace eigenvalue \(\lambda = \frac{1}{4}+R^{2}\), the number $R$ is said to be the **spectral parameter** of \(f\).

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- Review status: reviewed
- Last edited by Nathan Ryan on 2019-05-01 11:18:47

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**History:**(expand/hide all)

- 2019-05-01 11:18:47 by Nathan Ryan (Reviewed)
- 2019-05-01 11:14:49 by Nathan Ryan (Reviewed)
- 2011-09-06 05:50:21 by Holly Swisher

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