show · mf.base_change all knowls · up · search:

Let $K \supseteq F$ be a finite extension of number fields, not necessarily Galois. Let $f$ be a modular form on $\GL(2)$ over $F$ of level $\mathfrak{N}$.

For a (nonzero) prime $\mathfrak{p} \nmid \mathfrak{N}$ of $F$, let $L_{\mathfrak{p}}(f,T)$ be the (good, degree 2) Euler factor at $\mathfrak{p}$. For $r \in \Z_{\geq 1}$ and a polynomial $h(T) \in \C[T]$, let $h^{(r)}(T)$ be the polynomial whose roots are the $r$-th powers of the roots of $h(T)$ (with $\deg h^{(r)}(T)=\deg h(T)$).

We say that a modular form $g$ for $\GL(2)$ over $K$ is a base change of $f$ to $K$ if \[ L_{\mathfrak{q}}(g,T) = L_{\mathfrak{p}}^{(r)}(f,T) \] for all but finitely many primes $\mathfrak{q}$ of $K$, where $\mathfrak{q}$ lies over $\mathfrak{p} \nmid \mathfrak{N}$ and $r$ is the degree of $\mathfrak{q}$ over $\mathfrak{p}$.

In general, we say that a form $g$ for $\GL(2)$ over $K$ is a base change if there exists a proper subfield $K_0 \subsetneq K$ and a modular form $g_0$ on $\GL(2)$ over $K_0$ such that $g$ is the base change of $g_0$ to $K$.

In particular, if $g$ is a base change from $\Q$ to $K$, then $a_{\mathfrak{q}}(g) = a_{\sigma(\mathfrak{q})}(g)$ for all $\sigma \in \mathrm{Aut}(K)$.

Authors:
Knowl status:
  • Review status: beta
  • Last edited by John Voight on 2019-03-21 14:11:23
Referred to by:
History: (expand/hide all) Differences (show/hide)