If $G$ is a group, its inner automorphism group is a normal subgroup of the full automorphism group. Then, the **outer automorphism group** of $G$ is
\[ \mathrm{Out}(G) = \Aut(G)/\mathrm{Inn}(G).\]

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**Knowl status:**

- Review status: beta
- Last edited by John Jones on 2019-05-23 23:32:21

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