Properties

Label 4T3
Order \(8\)
n \(4\)
Cyclic No
Abelian No
Solvable Yes
Primitive No
$p$-group Yes
Group: $D_4$

Related objects

Group action invariants

Degree $n$ :  $4$
Transitive number $t$ :  $3$
Group :  $D_4$
CHM label :  $D(4)$
Parity:  $-1$
Primitive:  No
Generators:   (1,2,3,4), (1,3)
$|\Aut(F/K)|$:  $2$
Low degree resolvents:  
2: 2T1, 2T1, 2T1
4: 4T2

Subfields

Degree 2: $C_2$

Low degree siblings

4T3b, 8T4
A number field with this Galois group has no arithmetically equivalent fields.

Conjugacy Classes

Cycle TypeSizeOrderRepresentative
$ 1, 1, 1, 1 $ $1$ $1$ $()$
$ 2, 1, 1 $ $2$ $2$ $(2,4)$
$ 2, 2 $ $2$ $2$ $(1,2)(3,4)$
$ 4 $ $2$ $4$ $(1,2,3,4)$
$ 2, 2 $ $1$ $2$ $(1,3)(2,4)$

Group invariants

Order:  $8=2^{3}$
Cyclic:  No
Abelian:  No
Solvable:  Yes
GAP id:  [8, 3]
Character table:  
     2  3  2  2  2  3

       1a 2a 2b 4a 2c
    2P 1a 1a 1a 2c 1a
    3P 1a 2a 2b 4a 2c

X.1     1  1  1  1  1
X.2     1 -1 -1  1  1
X.3     1 -1  1 -1  1
X.4     1  1 -1 -1  1
X.5     2  .  .  . -2

Additional information

If a degree four extension of fields has this, 4T3, as its Galois group, then there is a non-isomorphic degree four extension with the same normal closure. 4T3 give the lowest degree example of this phenomenon.