# Properties

 Label 25T11 Order $$100$$ n $$25$$ Cyclic No Abelian No Solvable Yes Primitive No $p$-group No Group: $D_5.D_5$

## Group action invariants

 Degree $n$ : $25$ Transitive number $t$ : $11$ Group : $D_5.D_5$ Parity: $-1$ Primitive: No Nilpotency class: $-1$ (not nilpotent) Generators: (1,10,21,17)(2,9,22,16)(3,8,23,20)(4,7,24,19)(5,6,25,18)(11,14)(12,13), (1,4,2,5,3)(6,22,7,23,8,24,9,25,10,21)(11,20,12,16,13,17,14,18,15,19) $|\Aut(F/K)|$: $1$

## Low degree resolvents

|G/N|Galois groups for stem field(s)
2:  $C_2$
4:  $C_4$
10:  $D_{5}$
20:  $F_5$, 20T2

Resolvents shown for degrees $\leq 47$

## Subfields

Degree 5: $D_{5}$, $F_5$

## Low degree siblings

20T26

Siblings are shown with degree $\leq 47$

A number field with this Galois group has no arithmetically equivalent fields.

## Conjugacy Classes

 Cycle Type Size Order Representative $1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1$ $1$ $1$ $()$ $2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 1, 1, 1, 1, 1$ $5$ $2$ $( 6,24)( 7,25)( 8,21)( 9,22)(10,23)(11,17)(12,18)(13,19)(14,20)(15,16)$ $4, 4, 4, 4, 4, 2, 2, 1$ $25$ $4$ $( 2, 5)( 3, 4)( 6,11,24,17)( 7,15,25,16)( 8,14,21,20)( 9,13,22,19) (10,12,23,18)$ $4, 4, 4, 4, 4, 2, 2, 1$ $25$ $4$ $( 2, 5)( 3, 4)( 6,17,24,11)( 7,16,25,15)( 8,20,21,14)( 9,19,22,13) (10,18,23,12)$ $5, 5, 5, 5, 5$ $2$ $5$ $( 1, 2, 3, 4, 5)( 6, 7, 8, 9,10)(11,12,13,14,15)(16,17,18,19,20) (21,22,23,24,25)$ $10, 10, 5$ $10$ $10$ $( 1, 2, 3, 4, 5)( 6,25, 8,22,10,24, 7,21, 9,23)(11,18,13,20,15,17,12,19,14,16)$ $5, 5, 5, 5, 5$ $2$ $5$ $( 1, 3, 5, 2, 4)( 6, 8,10, 7, 9)(11,13,15,12,14)(16,18,20,17,19) (21,23,25,22,24)$ $10, 10, 5$ $10$ $10$ $( 1, 3, 5, 2, 4)( 6,21,10,25, 9,24, 8,23, 7,22)(11,19,15,18,14,17,13,16,12,20)$ $5, 5, 5, 5, 5$ $4$ $5$ $( 1, 6,15,19,23)( 2, 7,11,20,24)( 3, 8,12,16,25)( 4, 9,13,17,21) ( 5,10,14,18,22)$ $5, 5, 5, 5, 5$ $4$ $5$ $( 1, 7,12,17,22)( 2, 8,13,18,23)( 3, 9,14,19,24)( 4,10,15,20,25) ( 5, 6,11,16,21)$ $5, 5, 5, 5, 5$ $4$ $5$ $( 1, 8,14,20,21)( 2, 9,15,16,22)( 3,10,11,17,23)( 4, 6,12,18,24) ( 5, 7,13,19,25)$ $5, 5, 5, 5, 5$ $4$ $5$ $( 1, 9,11,18,25)( 2,10,12,19,21)( 3, 6,13,20,22)( 4, 7,14,16,23) ( 5, 8,15,17,24)$ $5, 5, 5, 5, 5$ $4$ $5$ $( 1,10,13,16,24)( 2, 6,14,17,25)( 3, 7,15,18,21)( 4, 8,11,19,22) ( 5, 9,12,20,23)$

## Group invariants

 Order: $100=2^{2} \cdot 5^{2}$ Cyclic: No Abelian: No Solvable: Yes GAP id: [100, 10]
 Character table:  2 2 2 2 2 1 1 1 1 . . . . . 5 2 1 . . 2 1 2 1 2 2 2 2 2 1a 2a 4a 4b 5a 10a 5b 10b 5c 5d 5e 5f 5g 2P 1a 1a 2a 2a 5b 5b 5a 5a 5d 5g 5e 5c 5f 3P 1a 2a 4b 4a 5b 10b 5a 10a 5f 5c 5e 5g 5d 5P 1a 2a 4a 4b 1a 2a 1a 2a 1a 1a 1a 1a 1a 7P 1a 2a 4b 4a 5b 10b 5a 10a 5d 5g 5e 5c 5f X.1 1 1 1 1 1 1 1 1 1 1 1 1 1 X.2 1 1 -1 -1 1 1 1 1 1 1 1 1 1 X.3 1 -1 A -A 1 -1 1 -1 1 1 1 1 1 X.4 1 -1 -A A 1 -1 1 -1 1 1 1 1 1 X.5 2 -2 . . B -B *B -*B *B B 2 B *B X.6 2 -2 . . *B -*B B -B B *B 2 *B B X.7 2 2 . . B B *B *B *B B 2 B *B X.8 2 2 . . *B *B B B B *B 2 *B B X.9 4 . . . 4 . 4 . -1 -1 -1 -1 -1 X.10 4 . . . C . *C . D /E -1 E /D X.11 4 . . . C . *C . /D E -1 /E D X.12 4 . . . *C . C . E D -1 /D /E X.13 4 . . . *C . C . /E /D -1 D E A = -E(4) = -Sqrt(-1) = -i B = E(5)^2+E(5)^3 = (-1-Sqrt(5))/2 = -1-b5 C = 2*E(5)^2+2*E(5)^3 = -1-Sqrt(5) = -1-r5 D = -E(5)-E(5)^2+E(5)^3 E = -E(5)-E(5)^3+E(5)^4