Properties

Label 15T21
Degree $15$
Order $360$
Cyclic no
Abelian no
Solvable no
Primitive no
$p$-group no
Group: $\GL(2,4):C_2$

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Show commands: Magma

magma: G := TransitiveGroup(15, 21);
 

Group action invariants

Degree $n$:  $15$
magma: t, n := TransitiveGroupIdentification(G); n;
 
Transitive number $t$:  $21$
magma: t, n := TransitiveGroupIdentification(G); t;
 
Group:  $\GL(2,4):C_2$
CHM label:   $3S_{5}(15)$
Parity:  $1$
magma: IsEven(G);
 
Primitive:  no
magma: IsPrimitive(G);
 
magma: NilpotencyClass(G);
 
$\card{\Aut(F/K)}$:  $1$
magma: Order(Centralizer(SymmetricGroup(n), G));
 
Generators:  (1,9,10,3,14)(2,15,7,12,6)(4,5,11,13,8), (1,2,15)(4,5,6)(8,9,10)(12,13,14), (1,4,10)(2,5,8)(3,7,11)(6,9,15)(12,14,13), (1,4)(2,6)(3,7)(5,15)(8,9)(12,13)
magma: Generators(G);
 

Low degree resolvents

|G/N|Galois groups for stem field(s)
$2$:  $C_2$
$6$:  $S_3$
$120$:  $S_5$

Resolvents shown for degrees $\leq 47$

Subfields

Degree 3: None

Degree 5: $S_5$

Low degree siblings

15T21, 15T22, 18T146, 30T89, 30T93 x 2, 30T101, 36T554, 45T45

Siblings are shown with degree $\leq 47$

A number field with this Galois group has exactly one arithmetically equivalent field.

Conjugacy classes

LabelCycle TypeSizeOrderRepresentative
$ 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1 $ $1$ $1$ $()$
$ 2, 2, 2, 2, 2, 2, 1, 1, 1 $ $30$ $2$ $( 3,15)( 4, 9)( 5,11)( 6, 8)( 7,10)(13,14)$
$ 3, 3, 3, 3, 1, 1, 1 $ $40$ $3$ $( 2, 3,15)( 4, 7, 5)( 9,11,10)(12,13,14)$
$ 4, 4, 4, 2, 1 $ $90$ $4$ $( 2, 5,12,11)( 3, 9,10,14)( 4,15,13, 7)( 6, 8)$
$ 2, 2, 2, 2, 2, 2, 1, 1, 1 $ $15$ $2$ $( 2, 5)( 3,13)( 4,10)( 7,14)( 9,15)(11,12)$
$ 15 $ $24$ $15$ $( 1, 2, 5, 3,12, 8, 9,15,11,14, 6, 4,10, 7,13)$
$ 6, 6, 3 $ $60$ $6$ $( 1, 2, 6, 9, 8, 4)( 3,10,12,11,15,14)( 5,13, 7)$
$ 6, 6, 3 $ $30$ $6$ $( 1, 2, 6, 4, 8, 9)( 3,14, 7,12,11,13)( 5,15,10)$
$ 5, 5, 5 $ $24$ $5$ $( 1, 2, 7,14, 5)( 3,13,15, 8, 9)( 4,11,12,10, 6)$
$ 3, 3, 3, 3, 3 $ $20$ $3$ $( 1, 2,12)( 3,11, 7)( 4,13, 6)( 5,10,15)( 8, 9,14)$
$ 15 $ $24$ $15$ $( 1, 2,13, 5,11, 6, 4,14,10, 3, 8, 9,12,15, 7)$
$ 3, 3, 3, 3, 3 $ $2$ $3$ $( 1, 6, 8)( 2, 4, 9)( 3, 7,11)( 5,10,15)(12,13,14)$

magma: ConjugacyClasses(G);
 

Group invariants

Order:  $360=2^{3} \cdot 3^{2} \cdot 5$
magma: Order(G);
 
Cyclic:  no
magma: IsCyclic(G);
 
Abelian:  no
magma: IsAbelian(G);
 
Solvable:  no
magma: IsSolvable(G);
 
Nilpotency class:   not nilpotent
Label:  360.120
magma: IdentifyGroup(G);
 
Character table:

1A 2A 2B 3A 3B 3C 4A 5A 6A 6B 15A1 15A-1
Size 1 15 30 2 20 40 90 24 30 60 24 24
2 P 1A 1A 1A 3A 3B 3C 2A 5A 3A 3B 15A1 15A-1
3 P 1A 2A 2B 1A 1A 1A 4A 5A 2A 2B 5A 5A
5 P 1A 2A 2B 3A 3B 3C 4A 1A 6A 6B 3A 3A
Type
360.120.1a R 1 1 1 1 1 1 1 1 1 1 1 1
360.120.1b R 1 1 1 1 1 1 1 1 1 1 1 1
360.120.2a R 2 2 0 1 2 1 0 2 1 0 1 1
360.120.4a R 4 0 2 4 1 1 0 1 0 1 1 1
360.120.4b R 4 0 2 4 1 1 0 1 0 1 1 1
360.120.5a R 5 1 1 5 1 1 1 0 1 1 0 0
360.120.5b R 5 1 1 5 1 1 1 0 1 1 0 0
360.120.6a R 6 2 0 6 0 0 0 1 2 0 1 1
360.120.6b1 C 6 2 0 3 0 0 0 1 1 0 12ζ15ζ152+ζ1532ζ154+ζ155ζ157 2+2ζ15+ζ152ζ153+2ζ154ζ155+ζ157
360.120.6b2 C 6 2 0 3 0 0 0 1 1 0 2+2ζ15+ζ152ζ153+2ζ154ζ155+ζ157 12ζ15ζ152+ζ1532ζ154+ζ155ζ157
360.120.8a R 8 0 0 4 2 1 0 2 0 0 1 1
360.120.10a R 10 2 0 5 2 1 0 0 1 0 0 0

magma: CharacterTable(G);