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Results (16 matches)

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Label Class Base field Conductor norm Rank Torsion CM Sato-Tate Regulator Period Leading coeff j-invariant Weierstrass coefficients Weierstrass equation
40.1-a1 40.1-a \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) 0 $\Z/4\Z$ $\mathrm{SU}(2)$ $1$ $4.406960782$ 1.137872381 \( \frac{237276}{625} \) \( \bigl[0\) , \( 0\) , \( 0\) , \( 13\) , \( -34\bigr] \) ${y}^2={x}^{3}+13{x}-34$
40.1-a2 40.1-a \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) 0 $\Z/2\Z\oplus\Z/2\Z$ $\mathrm{SU}(2)$ $1$ $17.62784313$ 1.137872381 \( \frac{148176}{25} \) \( \bigl[0\) , \( 0\) , \( 0\) , \( -7\) , \( -6\bigr] \) ${y}^2={x}^{3}-7{x}-6$
40.1-a3 40.1-a \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) 0 $\Z/4\Z$ $\mathrm{SU}(2)$ $1$ $35.25568626$ 1.137872381 \( \frac{55296}{5} \) \( \bigl[0\) , \( 0\) , \( 0\) , \( -2\) , \( 1\bigr] \) ${y}^2={x}^{3}-2{x}+1$
40.1-a4 40.1-a \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) 0 $\Z/2\Z$ $\mathrm{SU}(2)$ $1$ $4.406960782$ 1.137872381 \( \frac{132304644}{5} \) \( \bigl[0\) , \( 0\) , \( 0\) , \( -107\) , \( -426\bigr] \) ${y}^2={x}^{3}-107{x}-426$
40.1-b1 40.1-b \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) $2$ $\Z/2\Z$ $\mathrm{SU}(2)$ $0.638218348$ $8.151961419$ 2.686678917 \( \frac{237276}{625} \) \( \bigl[a + 1\) , \( a - 1\) , \( 0\) , \( -23 a + 115\) , \( -240 a + 955\bigr] \) ${y}^2+\left(a+1\right){x}{y}={x}^{3}+\left(a-1\right){x}^{2}+\left(-23a+115\right){x}-240a+955$
40.1-b2 40.1-b \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) $2$ $\Z/2\Z\oplus\Z/2\Z$ $\mathrm{SU}(2)$ $0.638218348$ $32.60784567$ 2.686678917 \( \frac{148176}{25} \) \( \bigl[a + 1\) , \( a - 1\) , \( 0\) , \( 17 a - 40\) , \( -57 a + 246\bigr] \) ${y}^2+\left(a+1\right){x}{y}={x}^{3}+\left(a-1\right){x}^{2}+\left(17a-40\right){x}-57a+246$
40.1-b3 40.1-b \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) $2$ $\Z/2\Z$ $\mathrm{SU}(2)$ $0.159554587$ $16.30392283$ 2.686678917 \( \frac{55296}{5} \) \( \bigl[0\) , \( 0\) , \( 0\) , \( 64 a - 248\) , \( 504 a - 1952\bigr] \) ${y}^2={x}^{3}+\left(64a-248\right){x}+504a-1952$
40.1-b4 40.1-b \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) $2$ $\Z/4\Z$ $\mathrm{SU}(2)$ $0.638218348$ $32.60784567$ 2.686678917 \( \frac{132304644}{5} \) \( \bigl[a + 1\) , \( a - 1\) , \( 0\) , \( 217 a - 815\) , \( -3552 a + 13781\bigr] \) ${y}^2+\left(a+1\right){x}{y}={x}^{3}+\left(a-1\right){x}^{2}+\left(217a-815\right){x}-3552a+13781$
40.1-c1 40.1-c \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) 0 $\Z/2\Z$ $\mathrm{SU}(2)$ $1$ $4.406960782$ 2.275744762 \( \frac{237276}{625} \) \( \bigl[a + 1\) , \( a - 1\) , \( a + 1\) , \( -24 a + 107\) , \( 295 a - 1123\bigr] \) ${y}^2+\left(a+1\right){x}{y}+\left(a+1\right){y}={x}^{3}+\left(a-1\right){x}^{2}+\left(-24a+107\right){x}+295a-1123$
40.1-c2 40.1-c \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) 0 $\Z/2\Z\oplus\Z/2\Z$ $\mathrm{SU}(2)$ $1$ $17.62784313$ 2.275744762 \( \frac{148176}{25} \) \( \bigl[a + 1\) , \( a - 1\) , \( a + 1\) , \( 16 a - 48\) , \( 37 a - 124\bigr] \) ${y}^2+\left(a+1\right){x}{y}+\left(a+1\right){y}={x}^{3}+\left(a-1\right){x}^{2}+\left(16a-48\right){x}+37a-124$
40.1-c3 40.1-c \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) 0 $\Z/4\Z$ $\mathrm{SU}(2)$ $1$ $35.25568626$ 2.275744762 \( \frac{55296}{5} \) \( \bigl[0\) , \( 0\) , \( 0\) , \( 64 a - 248\) , \( -504 a + 1952\bigr] \) ${y}^2={x}^{3}+\left(64a-248\right){x}-504a+1952$
40.1-c4 40.1-c \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) 0 $\Z/2\Z$ $\mathrm{SU}(2)$ $1$ $4.406960782$ 2.275744762 \( \frac{132304644}{5} \) \( \bigl[a + 1\) , \( a - 1\) , \( a + 1\) , \( 216 a - 823\) , \( 3157 a - 12209\bigr] \) ${y}^2+\left(a+1\right){x}{y}+\left(a+1\right){y}={x}^{3}+\left(a-1\right){x}^{2}+\left(216a-823\right){x}+3157a-12209$
40.1-d1 40.1-d \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) 0 $\Z/4\Z$ $\mathrm{SU}(2)$ $1$ $8.151961419$ 2.104827387 \( \frac{237276}{625} \) \( \bigl[0\) , \( 0\) , \( 0\) , \( 13\) , \( 34\bigr] \) ${y}^2={x}^{3}+13{x}+34$
40.1-d2 40.1-d \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) 0 $\Z/2\Z\oplus\Z/2\Z$ $\mathrm{SU}(2)$ $1$ $32.60784567$ 2.104827387 \( \frac{148176}{25} \) \( \bigl[0\) , \( 0\) , \( 0\) , \( -7\) , \( 6\bigr] \) ${y}^2={x}^{3}-7{x}+6$
40.1-d3 40.1-d \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) 0 $\Z/2\Z$ $\mathrm{SU}(2)$ $1$ $16.30392283$ 2.104827387 \( \frac{55296}{5} \) \( \bigl[0\) , \( 0\) , \( 0\) , \( -2\) , \( -1\bigr] \) ${y}^2={x}^{3}-2{x}-1$
40.1-d4 40.1-d \(\Q(\sqrt{15}) \) \( 2^{3} \cdot 5 \) 0 $\Z/4\Z$ $\mathrm{SU}(2)$ $1$ $32.60784567$ 2.104827387 \( \frac{132304644}{5} \) \( \bigl[0\) , \( 0\) , \( 0\) , \( -107\) , \( 426\bigr] \) ${y}^2={x}^{3}-107{x}+426$
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  *The rank, regulator and analytic order of Ш are not known for all curves in the database; curves for which these are unknown will not appear in searches specifying one of these quantities.