Basic invariants
| Dimension: | $4$ |
| Group: | $C_3^2:D_4$ |
| Conductor: | \(20525\)\(\medspace = 5^{2} \cdot 821 \) |
| Frobenius-Schur indicator: | $1$ |
| Root number: | $1$ |
| Artin number field: | Galois closure of 6.2.102625.1 |
| Galois orbit size: | $1$ |
| Smallest permutation container: | $C_3^2:D_4$ |
| Parity: | even |
| Projective image: | $\SOPlus(4,2)$ |
| Projective field: | Galois closure of 6.2.102625.1 |
Galois action
Roots of defining polynomial
The roots of $f$ are computed in an extension of $\Q_{ 19 }$ to precision 5.
Minimal polynomial of a generator $a$ of $K$ over $\mathbb{Q}_{ 19 }$:
\( x^{2} + 18x + 2 \)
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Roots:
| $r_{ 1 }$ | $=$ |
\( 2 + 5\cdot 19 + 2\cdot 19^{2} + 6\cdot 19^{3} + 14\cdot 19^{4} +O(19^{5})\)
|
| $r_{ 2 }$ | $=$ |
\( 13 a + 16 + \left(16 a + 14\right)\cdot 19 + \left(7 a + 18\right)\cdot 19^{2} + \left(5 a + 16\right)\cdot 19^{3} + \left(18 a + 3\right)\cdot 19^{4} +O(19^{5})\)
|
| $r_{ 3 }$ | $=$ |
\( 13 + 4\cdot 19 + 9\cdot 19^{2} + 6\cdot 19^{3} + 17\cdot 19^{4} +O(19^{5})\)
|
| $r_{ 4 }$ | $=$ |
\( 18 a + \left(a + 15\right)\cdot 19 + \left(16 a + 10\right)\cdot 19^{2} + \left(5 a + 11\right)\cdot 19^{3} + \left(8 a + 10\right)\cdot 19^{4} +O(19^{5})\)
|
| $r_{ 5 }$ | $=$ |
\( a + 18 + \left(17 a + 17\right)\cdot 19 + \left(2 a + 5\right)\cdot 19^{2} + \left(13 a + 1\right)\cdot 19^{3} + \left(10 a + 13\right)\cdot 19^{4} +O(19^{5})\)
|
| $r_{ 6 }$ | $=$ |
\( 6 a + 10 + \left(2 a + 18\right)\cdot 19 + \left(11 a + 9\right)\cdot 19^{2} + \left(13 a + 14\right)\cdot 19^{3} + 16\cdot 19^{4} +O(19^{5})\)
|
Generators of the action on the roots $r_1, \ldots, r_{ 6 }$
| Cycle notation |
Character values on conjugacy classes
| Size | Order | Action on $r_1, \ldots, r_{ 6 }$ | Character values |
| $c1$ | |||
| $1$ | $1$ | $()$ | $4$ |
| $6$ | $2$ | $(1,2)(3,4)(5,6)$ | $0$ |
| $6$ | $2$ | $(3,6)$ | $2$ |
| $9$ | $2$ | $(3,6)(4,5)$ | $0$ |
| $4$ | $3$ | $(1,4,5)$ | $1$ |
| $4$ | $3$ | $(1,4,5)(2,3,6)$ | $-2$ |
| $18$ | $4$ | $(1,2)(3,5,6,4)$ | $0$ |
| $12$ | $6$ | $(1,3,4,6,5,2)$ | $0$ |
| $12$ | $6$ | $(1,4,5)(3,6)$ | $-1$ |