Properties

Label 3.270400.12t33.a.b
Dimension $3$
Group $A_5$
Conductor $270400$
Root number $1$
Indicator $1$

Related objects

Downloads

Learn more

Basic invariants

Dimension: $3$
Group: $A_5$
Conductor: \(270400\)\(\medspace = 2^{6} \cdot 5^{2} \cdot 13^{2} \)
Frobenius-Schur indicator: $1$
Root number: $1$
Artin stem field: Galois closure of 5.1.270400.1
Galois orbit size: $2$
Smallest permutation container: $A_5$
Parity: even
Determinant: 1.1.1t1.a.a
Projective image: $A_5$
Projective stem field: Galois closure of 5.1.270400.1

Defining polynomial

$f(x)$$=$ \( x^{5} - 2x^{4} + 5x^{3} - 2x^{2} + 7x + 4 \) Copy content Toggle raw display .

The roots of $f$ are computed in an extension of $\Q_{ 31 }$ to precision 5.

Minimal polynomial of a generator $a$ of $K$ over $\mathbb{Q}_{ 31 }$: \( x^{2} + 29x + 3 \) Copy content Toggle raw display

Roots:
$r_{ 1 }$ $=$ \( 24 + 16\cdot 31 + 8\cdot 31^{2} + 17\cdot 31^{3} + 31^{4} +O(31^{5})\) Copy content Toggle raw display
$r_{ 2 }$ $=$ \( 11 a + 25 + \left(17 a + 24\right)\cdot 31 + \left(10 a + 18\right)\cdot 31^{2} + \left(a + 11\right)\cdot 31^{3} + \left(11 a + 6\right)\cdot 31^{4} +O(31^{5})\) Copy content Toggle raw display
$r_{ 3 }$ $=$ \( 17 a + 29 + \left(18 a + 6\right)\cdot 31 + \left(22 a + 8\right)\cdot 31^{2} + \left(18 a + 7\right)\cdot 31^{3} + \left(13 a + 9\right)\cdot 31^{4} +O(31^{5})\) Copy content Toggle raw display
$r_{ 4 }$ $=$ \( 20 a + 16 + \left(13 a + 17\right)\cdot 31 + \left(20 a + 22\right)\cdot 31^{2} + \left(29 a + 3\right)\cdot 31^{3} + \left(19 a + 27\right)\cdot 31^{4} +O(31^{5})\) Copy content Toggle raw display
$r_{ 5 }$ $=$ \( 14 a + 1 + \left(12 a + 27\right)\cdot 31 + \left(8 a + 3\right)\cdot 31^{2} + \left(12 a + 22\right)\cdot 31^{3} + \left(17 a + 17\right)\cdot 31^{4} +O(31^{5})\) Copy content Toggle raw display

Generators of the action on the roots $r_1, \ldots, r_{ 5 }$

Cycle notation
$(1,2,3)$
$(3,4,5)$

Character values on conjugacy classes

SizeOrderAction on $r_1, \ldots, r_{ 5 }$ Character value
$1$$1$$()$$3$
$15$$2$$(1,2)(3,4)$$-1$
$20$$3$$(1,2,3)$$0$
$12$$5$$(1,2,3,4,5)$$\zeta_{5}^{3} + \zeta_{5}^{2} + 1$
$12$$5$$(1,3,4,5,2)$$-\zeta_{5}^{3} - \zeta_{5}^{2}$

The blue line marks the conjugacy class containing complex conjugation.